Correct Answer: D
Explanation:
The given equation represents a beta-minus (β-) decay, where a neutron is converted into a proton, emitting an electron (e-) and an antineutrino (νe).
The equation is as follows:
\(_{83}^{210}\text{Bi} \rightarrow X + e^{-1} + \bar{v}\)
In β- decay, a neutron in the nucleus of the atom is transformed into a proton. The atomic number (Z) increases by 1, while the mass number (A) remains the same because a neutron is converted to a proton without a change in the total nucleon count.
In the equation for bismuth-210 (\(_{83}^{210}\text{Bi}\)), the atomic number is 83 and the mass number is 210. After the β- decay, the resulting element will have an atomic number of 84 (one proton more than 83), but the mass number will remain the same (210). This corresponds to the element polonium (Po), which has atomic number 84 and mass number 210.
The number of neutrons in the resulting nucleus can be found by subtracting the atomic number from the mass number:
Neutrons = Mass number - Atomic number = 210 - 84 = 126
Thus, the number of neutrons in the nucleus X is 126, which corresponds to the correct answer D.
In beta decay, a neutron is converted into a proton, emitting an electron (e⁻) and an antineutrino (\(\bar{\nu}\)). The number of protons in the nucleus increases by one while the number of neutrons decreases by one. In the given equation: \[ ^{210}_{83} \text{Bi} \rightarrow X + e^{-} + \bar{\nu} \] The atomic number of bismuth (Bi) is 83, and its mass number is 210. After beta decay, the new element \(X\) will have an atomic number of 84 (since one proton is added), and the mass number will remain 210 (since a neutron is converted into a proton). Therefore, the number of neutrons in the nucleus of \(X\) will be: \[ \text{Number of neutrons in } X = 210 - 84 = 126 \] Thus, the number of neutrons in the nucleus \(X\) is 126.
\(\textbf{Correct Answer:}\) \((D) \ 126\)
Match the LIST-I with LIST-II
LIST-I (Type of decay in Radioactivity) | LIST-II (Reason for stability) | ||
---|---|---|---|
A. | Alpha decay | III. | Nucleus is mostly heavier than Pb (Z=82) |
B. | Beta negative decay | IV. | Nucleus has too many neutrons relative to the number of protons |
C. | Gamma decay | I. | Nucleus has excess energy in an excited state |
D. | Positron Emission | II. | Nucleus has too many protons relative to the number of neutrons |
Choose the correct answer from the options given below:
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The density of the copper ($^{64}Cu$) nucleus is greater than that of the carbon ($^{12}C$) nucleus.
Reason (R): The nucleus of mass number A has a radius proportional to $A^{1/3}$.
In the light of the above statements, choose the most appropriate answer from the options given below: