Question

In the following equation representing β^- decay, the number of neutrons in the nucleus X is
\(_{83}^{210}\text{Bi}\rightarrow X+e^{-1}+\bar{v}\)

• A. 127
• B. 125
• C. 84
• D. 126

Answer 1

The Correct Option is D

Correct Answer: D

Explanation: 

The given equation represents a beta-minus (β^-) decay, where a neutron is converted into a proton, emitting an electron (e^-) and an antineutrino (ν_e).

The equation is as follows:

\(_{83}^{210}\text{Bi} \rightarrow X + e^{-1} + \bar{v}\)

In β^- decay, a neutron in the nucleus of the atom is transformed into a proton. The atomic number (Z) increases by 1, while the mass number (A) remains the same because a neutron is converted to a proton without a change in the total nucleon count.

In the equation for bismuth-210 (\(_{83}^{210}\text{Bi}\)), the atomic number is 83 and the mass number is 210. After the β^- decay, the resulting element will have an atomic number of 84 (one proton more than 83), but the mass number will remain the same (210). This corresponds to the element polonium (Po), which has atomic number 84 and mass number 210.

The number of neutrons in the resulting nucleus can be found by subtracting the atomic number from the mass number:

Neutrons = Mass number - Atomic number = 210 - 84 = 126

Thus, the number of neutrons in the nucleus X is 126, which corresponds to the correct answer D.