From the figure we know that,
\(OB = OC\) (as O is the center of the circle and \(OB , OC\) the radii of the circle)
\(∠ OBC = ∠ OCB = 37^∘\) (given in the question)
By angle sum property of the triangle,
\(∠BOC + ∠OBC + ∠OCB = 180^∘\)
\(∠BOC + 37^∘ + 37^∘ = 180^∘\)
\(∠ BOC = 180^∘ − 74^∘ = 106^∘\)
As we know that angle subtended by an arc at the center is double the angle subtended by it at any point on the circle.
\(∠ BOC = 2 × ∠ BAC\)
\(∠BAC = \frac{106}{2} = 53^∘\)
The correct option is (C): 53