From the figure we know that,
\(OB = OC\) (as O is the center of the circle and \(OB , OC\) the radii of the circle)
\(∠ OBC = ∠ OCB = 37^∘\) (given in the question)
By angle sum property of the triangle,
\(∠BOC + ∠OBC + ∠OCB = 180^∘\)
\(∠BOC + 37^∘ + 37^∘ = 180^∘\)
\(∠ BOC = 180^∘ − 74^∘ = 106^∘\)
As we know that angle subtended by an arc at the center is double the angle subtended by it at any point on the circle.
\(∠ BOC = 2 × ∠ BAC\)
\(∠BAC = \frac{106}{2} = 53^∘\)
The correct option is (C): 53
In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. Which one among the given options is the most appropriate combination of \( P \), \( Q \), and \( R \)?
Find the number of triangles in the given figure.
A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius \( r \) cm as shown in the figure. The side of the dodecagon is \( d \) cm. All the triangles (numbered 1 to 12 in the figure) are used to form squares of side \( r \) cm, and each numbered triangle is used only once to form a square. The number of squares that can be formed and the number of triangles required to form each square, respectively, are: