Based on the information provided and the geometric relationships described: 1. Let angle \( \angle HBG = 2y \) and \( \angle BAF = 2y \) (corresponding angles are equal). 2. \( \angle FAC = y \) and \( \angle CAB = 180^\circ - 2y \) (sum of angles in a triangle). 3. \( \angle ABG = y \) and \( \angle ABC = 90^\circ - y \). Given that \( \angle ACB \) (which is denoted as \( x \)) is not explicitly stated but inferred to be equal to \( \angle ABC \) due to geometric properties: \( \angle ACB = \angle ABC = 90^\circ - y \). Since \( 2x = 90^\circ \) (from the equation \( \angle ABC = 90^\circ - y \)), solving for \( x \): \( 2x = 90^\circ \) \( x = \frac{90^\circ}{2} \) \( x = 45^\circ \) Therefore, \( x = 45 \) degrees, which corresponds to answer option B 45.