
Side of square = Radius of arc = 10 cm
Now, area of shaded region =\(2\times[ area (sector ABD) -area ( \Delta ABD)]\)
⇒\(2\times[ (\frac{\theta}{360^\circ}\times \pi r^2)-\frac{1}{2}\times b \times h]\)
⇒\(2\times[ (\frac{90^\circ}{360^\circ}\times \pi \times 100)-\frac{1}{2}\times 10 \times 10]\)
⇒ \(2\times(25\pi-50)\)
⇒\((50\pi-100)\space cm^2\)
The correct option is (C): \(50\pi-100\)
