To solve the problem, we need to determine what physical quantity B represents in the equation AB = C, where A is the current density and C is the electric field.
1. Understanding the Given Quantities:
We are given:
- A = Current density (J) with units A/m²
- C = Electric field (E) with units V/m
- The equation relating them: AB = C
2. Dimensional Analysis:
Let's analyze the units of the equation:
J × B = E
(A/m²) × [B] = V/m
Therefore, the units of B must be:
[B] = (V/m)/(A/m²) = V·m/A
3. Relating to Known Physical Quantities:
The unit V·m/A is equivalent to Ω·m (ohm-meter), which is the unit of:
- Electrical resistivity (ρ)
This comes from the microscopic form of Ohm's Law:
E = ρJ
4. Comparing with Given Equation:
Our given equation is:
AB = C → JB = E
Ohm's Law states:
E = ρJ
Therefore, we can conclude:
B = ρ
5. Verification:
Let's verify the units:
- ρ has units of Ω·m
- Our dimensional analysis showed B must have units of V·m/A
Since 1 Ω = 1 V/A, the units match perfectly.
Final Answer:
B represents the resistivity (ρ) of the material.
A coil of area A and N turns is rotating with angular velocity \( \omega\) in a uniform magnetic field \(\vec{B}\) about an axis perpendicular to \( \vec{B}\) Magnetic flux \(\varphi \text{ and induced emf } \varepsilon \text{ across it, at an instant when } \vec{B} \text{ is parallel to the plane of the coil, are:}\)
Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of $\frac{1}{\sqrt{2}}$ Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of $10 \mathrm{~cm} / \mathrm{s}$, induced emf between points A and E is _______ mV.} 
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where