Question

In the electron emission process, \( _{Z}^{A}X \rightarrow _{Z+1}^{A}Y + e^{-} + \bar{\nu} \), the particle \( q \) emitted along with the electron is:

• A. Neutron
• B. Neutrino
• C. Antineutrino
• D. Proton
• E. Positron

Hint:

Beta decay involves the emission of an antineutrino to conserve energy and lepton number.

Answer 1

The Correct Option is C

In beta-minus (\( \beta^- \)) decay, a neutron in the nucleus transforms into a proton, emitting an electron and an antineutrino (\(\bar{\nu}\)). 
The reaction follows: \[ n \rightarrow p + e^{-} + \bar{\nu} \] The antineutrino is emitted to ensure the conservation of energy, angular momentum, and lepton number.