Zn(s)→ Zn2+(aq)+2e- ; \(E^\ominus\) = 0.76 V
Ag2O(s)+H2O(l)+2e- → 2Ag(s)+2OH-(aq) ; \(E^\ominus\) = 0.344 V
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Zn(s)+ Ag2O(s)+H2O(l)→ Zn2+(aq)+2Ag(s)+2OH-(aq); \(E^\ominus\) = 1.104 V
\(E^\ominus\)= 1.104 V
We know that,
\(\triangle_rG^\ominus=-nFE^\ominus\)
= - 2 × 96487 × 1.04
= - 213043.296 J
= - 213.04 kJ
Standard electrode potential for \( \text{Sn}^{4+}/\text{Sn}^{2+} \) couple is +0.15 V and that for the \( \text{Cr}^{3+}/\text{Cr} \) couple is -0.74 V. The two couples in their standard states are connected to make a cell. The cell potential will be:
To calculate the cell potential (\( E^\circ_{\text{cell}} \)), we use the standard electrode potentials of the given redox couples.
Given data:
\( E^\circ_{\text{Sn}^{4+}/\text{Sn}^{2+}} = +0.15V \)
\( E^\circ_{\text{Cr}^{3+}/\text{Cr}} = -0.74V \)
Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells.
Read More: Products of Electrolysis