Question:

In set of reactions, identify D
Chemical Reactions

Updated On: Apr 10, 2025
  • Option A
  • Option B
  • Option C
  • Option D
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The Correct Option is D

Approach Solution - 1

Looking at the reaction steps:

  1. The reaction of CH3COOH with SOCl2 will result in the conversion of the carboxyl group (–COOH) into an acyl chloride, forming A (C6H5COCl).
  2. This acyl chloride then undergoes Friedel–Crafts acylation with benzene in the presence of AlCl3 to form B (C6H5COCH2), where the acyl group is added to the benzene ring. 
  3. Next, compound B reacts with HCN, resulting in the formation of a nitrile group (-CN) at the benzylic position, forming compound C (C6H5CH(C2CH3)CN).
  4. Finally, hydrolysis of C with water leads to the formation of D, where the nitrile group is converted to a carboxyl group, yielding compound D (C6H5CH(C2CH3)COOH).

The correct answer is (D) : Option D.

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Approach Solution -2

To solve this problem, we must analyze the sequence of reactions and identify the final product D.

1. Reaction of $CH_3COOH$ with $SOCl_2$:
Acetic acid ($CH_3COOH$) reacts with thionyl chloride ($SOCl_2$) to form acetyl chloride ($CH_3COCl$). This is the compound A.

2. Reaction of Acetyl Chloride with Benzene in the presence of $AlCl_3$:
Acetyl chloride reacts with benzene in the presence of anhydrous aluminum chloride ($AlCl_3$) in a Friedel-Crafts acylation reaction. This forms acetophenone ($C_6H_5COCH_3$). This is the compound B.

3. Reaction of Acetophenone with $HCN$:
Acetophenone reacts with hydrogen cyanide ($HCN$) via nucleophilic addition to the carbonyl group. The cyanide ion ($CN^-$) attacks the carbonyl carbon, and a proton is transferred to the oxygen to form a cyanohydrin. The product is 2-hydroxy-2-phenylpropanenitrile, which has the structure $C_6H_5C(OH)(CN)CH_3$. This is the compound C.

4. Hydrolysis of Cyanohydrin:
Hydrolysis of the cyanohydrin with water converts the nitrile group (-CN) to a carboxylic acid group (-COOH). Thus, $C_6H_5C(OH)(CN)CH_3$ becomes $C_6H_5C(OH)(COOH)CH_3$. The product is 2-hydroxy-2-phenylpropanoic acid, which has the structure $C_6H_5C(COOH)(OH)CH_3$. This is the compound D.

5. Analyzing the Options:
Comparing the structure of compound D ($C_6H_5C(COOH)(OH)CH_3$) with the given options, we find that it matches option (D).

Final Answer:
The compound D is option (D).

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