Looking at the reaction steps:
The correct answer is (D) : .
To solve this problem, we must analyze the sequence of reactions and identify the final product D.
1. Reaction of $CH_3COOH$ with $SOCl_2$:
Acetic acid ($CH_3COOH$) reacts with thionyl chloride ($SOCl_2$) to form acetyl chloride ($CH_3COCl$). This is the compound A.
2. Reaction of Acetyl Chloride with Benzene in the presence of $AlCl_3$:
Acetyl chloride reacts with benzene in the presence of anhydrous aluminum chloride ($AlCl_3$) in a Friedel-Crafts acylation reaction. This forms acetophenone ($C_6H_5COCH_3$). This is the compound B.
3. Reaction of Acetophenone with $HCN$:
Acetophenone reacts with hydrogen cyanide ($HCN$) via nucleophilic addition to the carbonyl group. The cyanide ion ($CN^-$) attacks the carbonyl carbon, and a proton is transferred to the oxygen to form a cyanohydrin. The product is 2-hydroxy-2-phenylpropanenitrile, which has the structure $C_6H_5C(OH)(CN)CH_3$. This is the compound C.
4. Hydrolysis of Cyanohydrin:
Hydrolysis of the cyanohydrin with water converts the nitrile group (-CN) to a carboxylic acid group (-COOH). Thus, $C_6H_5C(OH)(CN)CH_3$ becomes $C_6H_5C(OH)(COOH)CH_3$. The product is 2-hydroxy-2-phenylpropanoic acid, which has the structure $C_6H_5C(COOH)(OH)CH_3$. This is the compound D.
5. Analyzing the Options:
Comparing the structure of compound D ($C_6H_5C(COOH)(OH)CH_3$) with the given options, we find that it matches option (D).
Final Answer:
The compound D is option (D).
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
A hydrocarbon which does not belong to the same homologous series of carbon compounds is
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is