Looking at the reaction steps:
The correct answer is (D) : .
To solve this problem, we must analyze the sequence of reactions and identify the final product D.
1. Reaction of $CH_3COOH$ with $SOCl_2$:
Acetic acid ($CH_3COOH$) reacts with thionyl chloride ($SOCl_2$) to form acetyl chloride ($CH_3COCl$). This is the compound A.
2. Reaction of Acetyl Chloride with Benzene in the presence of $AlCl_3$:
Acetyl chloride reacts with benzene in the presence of anhydrous aluminum chloride ($AlCl_3$) in a Friedel-Crafts acylation reaction. This forms acetophenone ($C_6H_5COCH_3$). This is the compound B.
3. Reaction of Acetophenone with $HCN$:
Acetophenone reacts with hydrogen cyanide ($HCN$) via nucleophilic addition to the carbonyl group. The cyanide ion ($CN^-$) attacks the carbonyl carbon, and a proton is transferred to the oxygen to form a cyanohydrin. The product is 2-hydroxy-2-phenylpropanenitrile, which has the structure $C_6H_5C(OH)(CN)CH_3$. This is the compound C.
4. Hydrolysis of Cyanohydrin:
Hydrolysis of the cyanohydrin with water converts the nitrile group (-CN) to a carboxylic acid group (-COOH). Thus, $C_6H_5C(OH)(CN)CH_3$ becomes $C_6H_5C(OH)(COOH)CH_3$. The product is 2-hydroxy-2-phenylpropanoic acid, which has the structure $C_6H_5C(COOH)(OH)CH_3$. This is the compound D.
5. Analyzing the Options:
Comparing the structure of compound D ($C_6H_5C(COOH)(OH)CH_3$) with the given options, we find that it matches option (D).
Final Answer:
The compound D is option (D).
Complete the following equation :
Write the products of the following reactions:
Predict the major product $ P $ in the following sequence of reactions:
(i) HBr, benzoyl peroxide
(ii) KCN
(iii) Na(Hg), $C_{2}H_{5}OH$