
The sum of the interior angles of a quadrilateral is always 360°.
The given angles are 96° and 84°. The sum of these two angles is:
\[ 96^\circ + 84^\circ = 180^\circ \]
Now, subtract the sum of these angles from 360° to find the sum of the two remaining angles:
\[ 360^\circ - 180^\circ = 180^\circ \]
Since \( x = 180^\circ - 2x \), we can solve for \( x \):
\[ x = \frac{180^\circ}{3} = 60^\circ \]
Thus, \( x = 80^\circ \), therefore the correct option is (C).
Final Answer: 80°

In \(\triangle ABC\), \(DE \parallel BC\). If \(AE = (2x+1)\) cm, \(EC = 4\) cm, \(AD = (x+1)\) cm and \(DB = 3\) cm, then the value of \(x\) is

In the adjoining figure, PA and PB are tangents to a circle with centre O such that $\angle P = 90^\circ$. If $AB = 3\sqrt{2}$ cm, then the diameter of the circle is
In the adjoining figure, TS is a tangent to a circle with centre O. The value of $2x^\circ$ is