>
Exams
>
Metallurgy
>
Fundamental Process of Ore Refining
>
in parkes process desilvering of molten lead is af
Question:
In Parkes process, desilvering of molten lead is affected by the addition of
Show Hint
Zinc's ability to form an alloy with silver makes it effective in the desilvering process in lead refining.
AP PGECET - 2024
AP PGECET
Updated On:
May 5, 2025
Carbon
Copper
Aluminum
Zinc
Hide Solution
Verified By Collegedunia
The Correct Option is
D
Solution and Explanation
In the Parkes process, zinc is added to molten lead to help remove silver by forming an alloy with silver that can be easily separated.
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Fundamental Process of Ore Refining
The process of cementation involves:
TS PGECET - 2024
Metallurgical Engineering
Fundamental Process of Ore Refining
View Solution
Titanium is produced by:
TS PGECET - 2024
Metallurgical Engineering
Fundamental Process of Ore Refining
View Solution
Sulphide shape control in steel making is done by adding:
TS PGECET - 2024
Metallurgical Engineering
Fundamental Process of Ore Refining
View Solution
Which of the following is a suitable method to remove hydrogen from molten aluminium?
TS PGECET - 2024
Metallurgical Engineering
Fundamental Process of Ore Refining
View Solution
Metallurgical coke is charged to:
TS PGECET - 2024
Metallurgical Engineering
Fundamental Process of Ore Refining
View Solution
View More Questions
Questions Asked in AP PGECET exam
The absolute humidity of air at 101.325 kPa is measured to be 0.02 kg of water per kg of dry air. Then the partial pressure of water vapour in the air is:
AP PGECET - 2025
Thermodynamics
View Solution
If the vapour pressure at two temperatures of a solid phase in equilibrium with its liquid phase is known, then the latent heat of fusion can be calculated by the:
AP PGECET - 2025
Thermodynamics
View Solution
1 mole of Argon gas is heated at constant pressure from 200 K to 600 K.
If \( C_p = 4\ \text{cal} \cdot \text{deg}^{-1} \cdot \text{mol}^{-1} \), then the change in entropy will be:
(Given \( \ln 3 = 1.09 \))
AP PGECET - 2025
Thermodynamics
View Solution
The minimum amount of work required to operate a refrigerator which removes 1000 Cal heat at $0^\circ$C and rejects at $50^\circ$C will be:
AP PGECET - 2025
Thermodynamics
View Solution
The entropy of single crystalline Silicon at absolute zero will be:
AP PGECET - 2025
Thermodynamics
View Solution
View More Questions