To determine the correct amount of solvent in a molal solution, we need to understand the concept of molality. Molality (m) is defined as the number of moles of solute per kilogram of solvent. Mathematically, it is expressed as:
\(m = \frac {moles\ of \ solute}{kilograms\ of \ solvent}\)
For a 1 molal solution, the molality is 1 mol/kg. Given the problem:
Using the definition of molality, we set up the equation:
1 = 0.5 / (kilograms of solvent)
To solve for the kilograms of solvent:
kilograms of solvent = \(\frac {0.5}{1}\) = 0.5 kg
Since 1 kilogram equals 1000 grams, we convert the kilograms of solvent into grams:
0.5 kg = 500 g
Therefore, the solution contains 500 g of solvent, which matches the option: 500 g of solvent.
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
What is Microalbuminuria ?
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: