To determine the correct amount of solvent in a molal solution, we need to understand the concept of molality. Molality (m) is defined as the number of moles of solute per kilogram of solvent. Mathematically, it is expressed as:
\(m = \frac {moles\ of \ solute}{kilograms\ of \ solvent}\)
For a 1 molal solution, the molality is 1 mol/kg. Given the problem:
Using the definition of molality, we set up the equation:
1 = 0.5 / (kilograms of solvent)
To solve for the kilograms of solvent:
kilograms of solvent = \(\frac {0.5}{1}\) = 0.5 kg
Since 1 kilogram equals 1000 grams, we convert the kilograms of solvent into grams:
0.5 kg = 500 g
Therefore, the solution contains 500 g of solvent, which matches the option: 500 g of solvent.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: