Kolbe's reaction involves the electrolysis of a sodium phenate solution in the presence of carbon dioxide \((CO_2)\).
Sodium phenate is derived from phenol \((\text{C}_6\text{H}_5\text{OH})\) by treating it with sodium hydroxide \((NaOH)\). When sodium phenate is electrolyzed, it undergoes decarboxylation in the presence of CO2, resulting in the formation of sodium salicylate.
The reaction can be represented as follows:
\(2 \text{C}_6\text{H}_5\text{ONa} + 2 \text{CO}_2 \rightarrow 2 \text{C}_7\text{H}_5\text{O}_3\text{Na} + \text{O}_2\)
This reaction is an important step in the synthesis of salicylic acid and related compounds.
Therefore, the correct reacting substances in Kolbe's reaction are sodium phenate and CO2 (option B).
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |
List-I | List-II | ||
(A) | [Co(NH3)5(NO2)]Cl2 | (I) | Solvate isomerism |
(B) | [Co(NH3)5(SO4)]Br | (II) | Linkage isomerism |
(C) | [Co(NH3)6] [Cr(CN)6] | (III) | Ionization isomerism |
(D) | [Co(H2O)6]Cl3 | (IV) | Coordination isomerism |