Question:

In hydrogen a atom, an electron is revolving in the orbit of radius $0.53\,�$ with $6.6 \times 10^{15}$ radiations/s. Magnetic field produced at the centre of the orbit is

Updated On: Apr 15, 2024
  • $0.125 \, Wb/m^2$
  • $1.25 \, Wb/m^2$
  • $12.5 \, Wb/m^2$
  • $125 \, Wb/m^2$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The magnetic field
$ B= \frac{\mu_{0}}{4\pi} . \frac{2\pi\left(qv\right)}{r} $
$= 10^{-7} \times \frac{2\times 3.14\times \left(1.6\times 10^{-19}\times 1.6\times 10^{15}\right)}{0.53\times 10^{-10}}$
$ = 12.5\, Wb/m^{3}$
Was this answer helpful?
0
0

Top Questions on Magnetic Field Due To A Current Element, Biot-Savart Law

View More Questions

Concepts Used:

Biot Savart Law

Biot-Savart’s law is an equation that gives the magnetic field produced due to a current-carrying segment. This segment is taken as a vector quantity known as the current element. In other words, Biot-Savart Law states that if a current carrying conductor of length dl produces a magnetic field dB, the force on another similar current-carrying conductor depends upon the size, orientation and length of the first current carrying element. 

The equation of Biot-Savart law is given by,

\(dB = \frac{\mu_0}{4\pi} \frac{Idl sin \theta}{r^2}\)

Application of Biot Savart law

  • Biot Savart law is used to evaluate magnetic response at the molecular or atomic level.
  • It is used to assess the velocity in aerodynamic theory induced by the vortex line.

Importance of Biot-Savart Law

  • Biot-Savart Law is exactly similar to Coulomb's law in electrostatics.
  • Biot-Savart Law is relevant for very small conductors to carry current,
  • For symmetrical current distribution, Biot-Savart Law is applicable.

For detailed derivation on Biot Savart Law, read more