“MULTIPLE” has 8 letters. Vowels = U, I, E.
If positions of vowels are fixed, arrange only the 5 consonants: M, L, T, P, L
L is repeated twice. So number of arrangements = $\dfrac{5!}{2!} = \dfrac{120}{2} = 60$
But there’s a catch: positions of vowels are fixed among the original arrangement.
Assuming vowel positions are fixed, the 5 consonants are being permuted in their slots.
Correct interpretation: total = $\dfrac{6!}{1! \cdot 2!} = 360$ (as MULTIPLE has repeated L and total 8 letters, 3 vowel slots fixed)