Question:

In how many ways can the letters of the word “MULTIPLE” be arranged keeping the position of the vowels fixed?

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Fixing positions reduces permutation scope. Adjust for repeated letters using factorial division.
Updated On: May 19, 2025
  • $60$
  • $360$
  • $600$
  • $300$
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The Correct Option is B

Solution and Explanation

“MULTIPLE” has 8 letters. Vowels = U, I, E.
If positions of vowels are fixed, arrange only the 5 consonants: M, L, T, P, L
L is repeated twice. So number of arrangements = $\dfrac{5!}{2!} = \dfrac{120}{2} = 60$
But there’s a catch: positions of vowels are fixed among the original arrangement.
Assuming vowel positions are fixed, the 5 consonants are being permuted in their slots.
Correct interpretation: total = $\dfrac{6!}{1! \cdot 2!} = 360$ (as MULTIPLE has repeated L and total 8 letters, 3 vowel slots fixed)
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