
It is given that, AB \(||\) CD.
EF \(⊥\) CD
\(∠\)GED = 126º
\(⇒\) ∠GEF + \(∠\)FED = 126º
\(⇒\) \(∠\)GEF + 90º = 126º
\(⇒\) \(∠\)GEF = 36º
\(∠\)AGE and \(∠\)GED are alternate interior angles.
\(⇒\) \(∠\)AGE = \(∠\)GED = 126º
However, \(∠\)AGE + \(∠\)FGE = 180º (Linear pair)
\(⇒\) 126º + \(∠\)FGE = 180º
\(⇒\)\(∠\)FGE = 180º − 126º = 54º
∴ \(∠\)AGE = 126º, \(∠\)GEF = 36º, \(∠\)FGE = 54º




Section | Number of girls per thousand boys |
|---|---|
Scheduled Caste (SC) | 940 |
Scheduled Tribe (ST) | 970 |
Non-SC/ST | 920 |
Backward districts | 950 |
Non-backward districts | 920 |
Rural | 930 |
Urban | 910 |
(i) Represent the information above by a bar graph.
(ii) In the classroom discuss what conclusions can be arrived at from the graph.

