
\(∠\)APR=\(∠\)PRD [Alternate interior angles]
50°+y=127°
y=127°−50°
y=77°
Also,
\(∠\)APQ=\(∠\)PQR [Alternate interior angles]
50°= x
\(∴\) x=50° and y=77°




(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
