1. Capacitance:
The capacitance of a capacitor is defined as the ratio of the charge stored to the potential difference across it:
$C = \frac{Q}{V}$
From the graph, we can see that when $V = 10\,\text{V}$, $Q = 120\,\mu\text{C}$. Therefore:
$C = \frac{120\,\mu\text{C}}{10\,\text{V}} = 12\,\mu\text{F}$
2. Energy Stored:
The energy stored in a capacitor can be calculated using the following formula:
$U = \frac{1}{2}CV^2 = \frac{1}{2}QV$
Using the values from the graph ($Q = 120\,\mu\text{C}$ and $V = 10\,\text{V}$):
$U = \frac{1}{2}(120 \times 10^{-6}\,\text{C})(10\,\text{V}) = 600\,\mu\text{J}$
Alternatively, using the calculated capacitance:
$U = \frac{1}{2}(12 \times 10^{-6}\,\text{F})(10\,\text{V})^2 = 600\,\mu\text{J}$
The correct answer is (B) 12 μF, 600 μJ.
Step 1: Determine Charge and Voltage from the Graph:
From the graph, we can observe a point where the potential difference (V) is 10V and the corresponding charge (Q) is 120 $\mu$C.
Step 2: Calculate Capacitance (C):
The relationship between charge, capacitance, and voltage for a capacitor is given by the formula:
$Q = CV$
To find the capacitance (C), we can rearrange the formula:
$C = \frac{Q}{V}$
Substitute the values from the graph:
$C = \frac{120 \ \mu C}{10 \ V}$
$C = 12 \ \mu F$
Step 3: Calculate Energy Stored (E):
The energy stored in a capacitor can be calculated using the formula:
$E = \frac{1}{2} QV$
Substitute the values of Q and V from the graph and the calculated capacitance:
$E = \frac{1}{2} \times (120 \ \mu C) \times (10 \ V)$
$E = \frac{1}{2} \times (120 \times 10^{-6} \ C) \times (10 \ V)$
$E = \frac{1}{2} \times 1200 \times 10^{-6} \ J$
$E = 600 \times 10^{-6} \ J$
$E = 600 \ \mu J$
Step 4: Match with the Options:
Comparing our calculated values with the given options:
(A) 12 $\mu$F, 1200 $\mu$J (Capacitance is correct, Energy is incorrect)
(B) 12 $\mu$F, 600 $\mu$J (Capacitance is correct, Energy is correct)
(C) 24 $\mu$F, 600 $\mu$J (Capacitance is incorrect, Energy is correct)
(D) 24 $\mu$F, 1200 $\mu$J (Capacitance is incorrect, Energy is incorrect)
Final Answer: Option (B) matches calculated capacitance and energy stored.
Identify the valid statements relevant to the given circuit at the instant when the key is closed.
\( \text{A} \): There will be no current through resistor R.
\( \text{B} \): There will be maximum current in the connecting wires.
\( \text{C} \): Potential difference between the capacitor plates A and B is minimum.
\( \text{D} \): Charge on the capacitor plates is minimum.
Choose the correct answer from the options given below:
A convex lens has power \( P \). It is cut into two halves along its principal axis. Further, one piece (out of two halves) is cut into two halves perpendicular to the principal axis as shown in the figure. Choose the incorrect option for the reported lens pieces.
The equation \[ 2 \cos^{-1} x = \sin^{-1} \left( 2 \sqrt{1 - x^2} \right) \] is valid for all values of \(x\) satisfying:
A metallic sphere of radius \( R \) carrying a charge \( q \) is kept at a certain distance from another metallic sphere of radius \( R_4 \) carrying a charge \( Q \). What is the electric flux at any point inside the metallic sphere of radius \( R \) due to the sphere of radius \( R_4 \)?