To solve this question, we need to understand the process of electrolytic refining of metals.
1. Electrolytic Refining of Metals:
In electrolytic refining, the metal to be refined is used as the anode. The pure metal is deposited at the cathode during the electrolysis process.
2. Process Overview:
- The impure metal is placed as the anode in an electrolyte solution. - When current is passed, the metal from the anode dissolves into the electrolyte solution, and pure metal is deposited at the cathode.
3. Evaluating the Options:
Final Answer:
The correct answer is (B) Cathode.
If E$_{cell}$ of the following reaction is x $\times$ 10$^{-1}$. Find x
\(\text{Pt/ HSnO$_2$ / Sn(OH)$_6^{2-}$, OH$^-$ / Bi$_2$O$_3$ / Bi / Pt}\)
\(\text{[Reaction Quotient, Q = 10$^6$]}\)
Given \( E^o_{\text{[Sn(OH)$_3$]}} \) = -0.90 V, \( E^o_{\text{Bi$_2$O$_3$ / Bi}} \) = -0.44 V
