In case of isoelectronic species the size of F– , Ne and Na+ is affected by:
- Principal quantum number (n)
- None of the factors because their size is the same
- Electron-electron interaction in the outer orbitals
- Nuclear charge (z)
The Correct Option is D
Solution and Explanation
In \( \text{F}^- \), Ne, and \( \text{Na}^+ \), all have \( 1s^2, 2s^2, 2p^6 \) configuration. They differ in size due to differences in nuclear charge, affecting their pull on electrons.
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