In the given problem, we need to determine how many boys appeared in an examination. Let's denote the number of girls as \( G \) and the number of boys as \( B \). The total number of students is \( G + B = 480 \).
We know 85% of the girls passed, and 70% of the boys passed. The overall pass percentage is 75%, meaning:
\(\frac{0.85G + 0.70B}{480} = 0.75\)
Multiply both sides by 480 to eliminate the fraction:
0.85G + 0.70B = 360
We also have the equation for the total number of students:
G + B = 480
Substituting \( G = 480 - B \) into the first equation:
0.85(480 - B) + 0.70B = 360
Expanding, we have:
408 - 0.85B + 0.70B = 360
Combining like terms gives:
408 - 0.15B = 360
Simplify by subtracting 408 from both sides:
- 0.15B = -48
Divide by -0.15 to solve for \( B \):
B = 320
Thus, the number of boys who appeared in the examination is 320.