Question:

In an examination, a question paper consists of 12 questions divided into two parts i.e., Part I and Part II, containing 5 and 7 questions, respectively. A student is required to attempt 8 questions in all, selecting at least 3 from each part. In how many ways can a student select the questions?

Updated On: Apr 1, 2024
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Solution and Explanation

It is given that the question paper consists of 12 questions divided into two parts - Part I and Part II, containing 5 and 7 questions, respectively.
A student has to attempt 8 questions, selecting at least 3 from each part.

This can be done as follows. 
(a) 3 questions from part I and 5 questions from part II 
(b) 4 questions from part I and 4 questions from part II 
(c) 5 questions from part I and 3 questions from part II

3 questions from part I and 5 questions from part II can be selected in \(^5C_3\times\space^7C_5\) ways.
4 questions from part I and 4 questions from part II can be selected in \(^5C_4 \times\space^7C_4\) ways.
4 questions from part I and 4 questions from part II can be selected in \(^5C_5\times\space^7C_3\) ways.
Thus, required number of ways of selecting questions
\(=\)\(^5C_3\times\space^7C_5+^5C_4\times\space^7C_4+^5C_5\times\space^7C_3\)

\(=\)\(\frac{5!}{2!3!}\times\frac{7!}{2!5!}+\frac{5!}{4!1!}\times\frac{7!}{4!3!}+\frac{5!}{5!0!}\times\frac{7!}{3!4!}\)

\(=210+175+35=420\)

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Combination:

Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.

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