Question:

In an equilateral triangle $A B C, F_{1}, F_{2}$ and $F_{3}$ are three forces acting along the sides $A B, B C$ and $A C$ as shown in the given figure. What should be the magnitude of $F_{3}$ so that the total torque about $O$ is zero?

Updated On: Jul 12, 2022
  • 2 N
  • 4 N
  • 6 N
  • 8 N
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The Correct Option is C

Solution and Explanation

The total torque about $O$ is given by or $ \tau =F_{1} d+F_{2} d-F_{3} d $ $ \Rightarrow F_{3} =F_{1}+F_{2} $ $=4+2 $ $=6\, N $ Here, $d$ is the perpendicular distance of $O$ from every side of the equilateral triangle.
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.