To determine how many pieces are under attack by the queen, we analyze the position of the queen and other pieces on the board.
Queen's Position: c5
Other Pieces: c2, g1, g3, g5, a3
Queen's Attack Pattern: The queen can attack in her row, column, and diagonals.
Hence, the pieces at positions c2, g5, a3, g3 are under attack by the queen. In total, 4 pieces are attacked.
To solve this problem, we must determine from how many positions a queen cannot attack any given piece on the chessboard. The positions of the pieces are: a1, a3, b4, d7, h7, and h8. Let's analyze each of these situations on a chessboard:
Analyzing positions not threatening any other piece. Consider the logical exclusions of overlapping attack vectors:
Position | Reason |
---|---|
c5 | No pieces on c column, 5th row, and its diagonals. |
d1 | Free from pieces along column, row, nor its direct diagonals because d7 is blocked. |
g3 | Lacks pieces on g column, 3rd row, or direct diagonals. |
f8 | Uninterrupted and free from paths or direct diagonals targeting from known pieces. |
Based on these observations, there are 4 positions (c5, d1, g3, f8) from which the queen cannot attack any of the pieces. Hence, the correct answer is 4.
An \(8 \times 8\) chessboard has: \[ 8 \times 8 = 64 \ \text{squares} \]
Total attackable: \[ 7 \ (\text{row}) + 7 \ (\text{column}) + 6 \ (\text{diagonal } \backslash) + 7 \ (\text{diagonal } /) = 27 \]
Note: The square d5 itself is not included in these counts.
\[ \text{Safe squares} = 64 - (\text{Attackable squares} + 1 \ \text{(queen’s own square)}) \] \[ = 64 - (27 + 1) = 64 - 28 = 36 \]
\[ \boxed{36} \]
The following histogram represents: