In a zero-order reaction,the reactant A disappeared with a rate of reaction k=0.04 Msec-1. The initial concentration of A is 1 M. What will be the concentration of A after 20 seconds?
1.08 M
0.2 M
0.8 M
0.002 M
0.008 M
Given parameters:
Zero-order rate equation: \[ [A]_t = [A]_0 - kt \] \[ [A]_t = 1 - (0.04 \times 20) \] \[ [A]_t = 1 - 0.8 = 0.2 \, \text{M} \]
Thus, the correct option is (B): 0.2 M.
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively:
The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.
Consider the reaction A → B,
Rate of the reaction is given by,
Rate = −d[A]/ dt=+d[B]/ dt
Where, [A] → concentration of reactant A
[B] → concentration of product B
(-) A negative sign indicates a decrease in the concentration of A with time.
(+) A positive sign indicates an increase in the concentration of B with time.
There are certain factors that determine the rate of a reaction: