Question

In a vernier calipers 50 VSD are equal to 48 MSD. 1 MSD is equal to $0.05$ mm. Find least count of this vernier calipers.

• A. $0.005$ mm
• B. $0.004$ mm
• C. $0.001$ mm
• D. $0.002$ mm

Hint:

Least count equals difference between one main scale division and one vernier scale division.

Answer 1

The Correct Option is D

Step 1: Relation between VSD and MSD.
\[ 1 \text{ VSD} = \dfrac{48}{50} \text{ MSD} \]
Step 2: Least count formula.
\[ LC = 1 \text{ MSD} - 1 \text{ VSD} \]
Step 3: Substituting values.
\[ LC = 1 \text{ MSD} - \dfrac{48}{50} \text{ MSD} = \dfrac{2}{50} \text{ MSD} \]
\[ LC = \dfrac{2}{50} \times 0.05 = 0.002 \text{ mm} \]