In a triangle, if the angles are in the ratio \( 3 : 2 : 1 \), then we can denote the angles of the triangle as \( 3\alpha, 2\alpha, \) and \( \alpha \), where \( \alpha \) is a constant.
By the property of the angles of a triangle, we know that the sum of all angles is \( 180^\circ \):
\[
3\alpha + 2\alpha + \alpha = 180^\circ.
\]
Simplifying the equation:
\[
6\alpha = 180^\circ \quad \Rightarrow \quad \alpha = 30^\circ.
\]
Thus, the angles of the triangle are:
\[
3\alpha = 90^\circ, \quad 2\alpha = 60^\circ, \quad \alpha = 30^\circ.
\]
Now, using the property of the sides of a triangle, we know that the sides opposite to the angles of \( 30^\circ, 60^\circ, 90^\circ \) are in the ratio \( 1 : \sqrt{3} : 2 \).
Thus, the ratio of the sides of the triangle is:
\[
2 : \sqrt{3} : 1.
\]