Question:
In a triangle \(ABC\), \(\displaystyle \frac{a(rr_1+r_2r_3)}{r_1-r+r_2r_3} =\;?\)
In a triangle \(ABC\), \(\displaystyle \frac{a(rr_1+r_2r_3)}{r_1-r+r_2r_3} =\;?\)
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Various exradius/inradius relationships lead to symmetrical expressions in side lengths and excenters.
- Memorizing or deriving the standard identities can be crucial for quick solving.
- Memorizing or deriving the standard identities can be crucial for quick solving.
Updated On: Mar 10, 2025
- \(\sqrt{rr_1r_2r_3}\)
- \(\frac{r_1 + r_2}{r_1 + r_3}\)
- \(2(R + r)\)
- \(\frac{p + \frac{r}{2R}}{\dots}\) [ truncated in the image ]
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