The resolution $R$ of a monochromator is defined as:
\[
R = \dfrac{\lambda}{\Delta \lambda}
\]
Where:
- $\lambda$ is the average wavelength
- $\Delta \lambda$ is the minimum difference between two wavelengths that the instrument can distinguish
Given:
$\lambda_1 = 599.9$ nm
$\lambda_2 = 600.1$ nm
Average wavelength $\lambda = \dfrac{599.9 + 600.1}{2} = 600$ nm
Difference $\Delta \lambda = 600.1 - 599.9 = 0.2$ nm
Now compute resolution:
\[
R = \dfrac{600}{0.2} = 3000
\]
Therefore, the required resolution of the monochromator is 3000.