Question:

In a solid $'AB'$ having the $NaCl$ structure, $'A'$ atoms occupy the corners of the cubic unit cell. If all the face centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

Updated On: Jun 14, 2022
  • $ AB_2 $
  • $ A_2 B $
  • $ A_4 B_3 $
  • $ A_3 B_4 $
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The Correct Option is D

Solution and Explanation

Atom A occupies all corner and face center of unit cell and atom B in all octahedral void. As all atoms from face center from one axis is removed, hence number of atom A in unit cell remains 3 and B as 4.

$A=8\times \frac{1}{8}+6\times \frac{1}{2}=4$
$A=4-2\times \frac{1}{2}=3$ after removing atoms

$B=12\times \frac{1}{4}+1\times 1=4$

Formula of compound is $A_{3}B_{4}$
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Concepts Used:

Solid State

Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions. 

Solid State

Types of Solids:

Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;

  • Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
  • Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.