Question:

In a school of more than 500 students, when the students were standing in a row of 7, 5 students were left out. When these students were standing in a row of 10, again 5 students were left out and when they were standing in a row of 15, 5 students were left out again. If each time, at least one row was formed and the number of students in the school is the least possible, then find the average of the number of rows formed in the above three cases.

Updated On: Sep 10, 2024
  • 70
  • 68
  • 55
  • 65
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The Correct Option is D

Solution and Explanation

The correct option is (D): 65.
From the given question, we can observe that in each case 5 students are being left out.
So, the number of students in the school will be
LCM of (7, 10 and 15) × k + 5 = 210k + 5
Also, it is given that the number of students in the school is more than 500.
So, if k = 1, number of students = 215 (not possible)
If k = 2, number of students = 420 + 5 = 425 (not possible)
If k = 3, number of students = 630 + 5 = 635 (possible)
After simplifying:
average =80.
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