In nuclear fusion, the mass of the product nucleus \( M_C \) is always less than the sum of the masses of the fusing nuclei \( M_A \) and \( M_B \). This is due to the fact that some of the mass is converted into energy, as per the mass-energy equivalence principle \( E = mc^2 \).
Thus, the correct answer is (A).
A small bob A of mass m is attached to a massless rigid rod of length 1 m pivoted at point P and kept at an angle of 60° with vertical. At 1 m below P, bob B is kept on a smooth surface. If bob B just manages to complete the circular path of radius R after being hit elastically by A, then radius R is_______ m :