In nuclear fusion, the mass of the product nucleus \( M_C \) is always less than the sum of the masses of the fusing nuclei \( M_A \) and \( M_B \). This is due to the fact that some of the mass is converted into energy, as per the mass-energy equivalence principle \( E = mc^2 \).
Thus, the correct answer is (A).
Mass Defect and Energy Released in the Fission of \( ^{235}_{92}\text{U} \)
When a neutron collides with \( ^{235}_{92}\text{U} \), the nucleus gives \( ^{140}_{54}\text{Xe} \) and \( ^{94}_{38}\text{Sr} \) as fission products, and two neutrons are ejected. Calculate the mass defect and the energy released (in MeV) in the process.
Given: