In a lottery containing 35 tickets, exactly 10 tickets bear a prize. If a ticket is drawn at random, then the probability of not getting a prize is
Show Hint
- $\dfrac{1}{10}$
- $\dfrac{2}{5}$
- $\dfrac{2}{7}$
- $\dfrac{5}{7}$
The Correct Option is D
Solution and Explanation
Number of prize-bearing tickets = 10
Number of non-prize tickets = $35 - 10 = 25$
Required probability = $\dfrac{25}{35} = \dfrac{5}{7}$
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