Question

In a defective 6 faced die with numbers 1 to 6 inscribed,probability of odd is 2 times that of even. What is the probability to gt number 5 in single throw?

• A. \(\frac{2}{9}\)
• B. \(\frac{4}{81}\)
• C. \(\frac{1}{3}\)
• D. \(\frac{1}{9}\)

Answer 1

The Correct Option is A

Prob of even + Prob of odd = 1 (total probability)
Prob of even + 2 (Prob of even) = 1
3(Prob of even) = 1

Prob of even = \(\frac{1}{3}\)

So, prob of odd = \(\frac{2}{3}\)

Since there are 3 odd numbers {1,3,5}.

So, Prob of getting 5 is \(\frac{1}{3}\)

Hence, getting 5 ( odd ) in a single throw is = \(\frac{2}{3}\times\frac{1}{3}=\frac{2}{9}\).
So the correct option is (A)