Question:

In a constant head permeameter, having cross-sectional area of $20 \, \text{cm}^2$, when the flow was taking place under a hydraulic gradient of $0.5$, the amount of water collected is $1200 \, \text{cm}^3$ in $60 \, \text{sec}$. The permeability of the soil is:

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Always apply Darcy's law directly for constant head permeability tests: $k = \dfrac{Q}{A \cdot i \cdot t}$.
Updated On: Sep 24, 2025
  • 0.002 cm/sec
  • 0.02 cm/sec
  • 0.2 cm/sec
  • 2 cm/sec
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The Correct Option is C

Solution and Explanation


Step 1: Recall Darcy's law.
For constant head test, \[ Q = k \cdot i \cdot A \cdot t \] where, $Q =$ volume of water collected, $k =$ coefficient of permeability, $i =$ hydraulic gradient, $A =$ cross-sectional area, $t =$ time.

Step 2: Substitute given values.
\[ Q = 1200 \, \text{cm}^3, A = 20 \, \text{cm}^2, i = 0.5, t = 60 \, \text{s}. \]

Step 3: Formula for $k$.
\[ k = \frac{Q}{A \cdot i \cdot t} = \frac{1200}{20 \cdot 0.5 \cdot 60}. \] \[ = \frac{1200}{600} = 0.2 \, \text{cm/sec}. \]

Step 4: Conclusion.
Thus, the permeability of the soil is $0.2 \, \text{cm/sec}$.

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