Question

In a certain code language, 'SUN RISES IN THE EAST' is written as '6T 5E 4N 7S 5N' and 'HOUSE OF MOHAN IS TOWARDS WEST' is written as '6T 9S 4S 7N 4F 7E'. How will 'RAM GOES TO SCHOOL' be written in that language?

• A. 6L 2O 4S 3M
• B. 8L 4O 6S 5M
• C. 5M 6S 4O 8L
• D. 6T 5M 4F 8E

Hint:

In mixed coding with numbers and letters, usually: - The number relates to the length of the word or the position of the first/last letter. - The letter is often the first, last, or middle letter of the word.

Answer 1

The Correct Option is B

Step 1: Understanding the Question:
This is a coding-decoding problem where numbers and letters are assigned to words based on specific properties of those words. We need to decode the logic using the given examples and apply it to "RAM GOES TO SCHOOL".
Step 2: Detailed Explanation:
Let's analyze the first sentence: "SUN RISES IN THE EAST" \(\rightarrow\) "6T 5E 4N 7S 5N". Let's look for patterns involving word length and letters.

Word: EAST (Length = 4, Last Letter = T). Code: 6T. Relationship: Number = Length + 2 \((4+2=6)\). Letter = Last Letter.
Word: THE (Length = 3, Last Letter = E). Code: 5E. Relationship: Number = \(3+2=5\). Letter = E.
Word: IN (Length = 2, Last Letter = N). Code: 4N. Relationship: Number = \(2+2=4\). Letter = N.
Word: SUN (Length = 3, Last Letter = N). Code: 5N. Relationship: Number = \(3+2=5\). Letter = N.
Word: RISES (Length = 5, Last Letter = S). Code: 7S. Relationship: Number = \(5+2=7\). Letter = S.
The logic is: Code = (Length of Word + 2) concatenated with (Last Letter of Word). Now, apply this logic to "RAM GOES TO SCHOOL":

RAM: Length = 3, Last = M. Code: \((3+2)\)M = 5M.
GOES: Length = 4, Last = S. Code: \((4+2)\)S = 6S.
TO: Length = 2, Last = O. Code: \((2+2)\)O = 4O.
SCHOOL: Length = 6, Last = L. Code: \((6+2)\)L = 8L.
The codes are 5M, 6S, 4O, 8L. The order in the option might vary. Looking at the options, Option (B) contains "8L 4O 6S 5M", which matches our derived codes.
Step 3: Final Answer:
The code is 8L 4O 6S 5M.