Question:

Four letter-cluster pairs have been given, out of which three are alike in some manner and one is different. Select the one that is different.

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Check the difference between corresponding letters (1st to 1st, 2nd to 2nd). Any deviation in the constant difference marks the odd one out.
Updated On: Feb 14, 2026
  • SHAR : UJCT
  • MIGH : OKIJ
  • BEYO : DGBQ
  • PHOB : RJQD
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
We need to find the odd pair by checking the letter shift pattern in each pair.
Step 2: Detailed Explanation:
Let's analyze the shift for each pair: (A) SHAR : UJCT

S (+2) \(\rightarrow\) U
H (+2) \(\rightarrow\) J
A (+2) \(\rightarrow\) C
R (+2) \(\rightarrow\) T
Pattern: All +2.
(B) MIGH : OKIJ

M (+2) \(\rightarrow\) O
I (+2) \(\rightarrow\) K
G (+2) \(\rightarrow\) I
H (+2) \(\rightarrow\) J
Pattern: All +2.
(C) BEYO : DGBQ

B (+2) \(\rightarrow\) D
E (+2) \(\rightarrow\) G
Y (+3) \(\rightarrow\) B (Y \(\rightarrow\) Z \(\rightarrow\) A \(\rightarrow\) B)
O (+2) \(\rightarrow\) Q
Pattern: +2, +2, +3, +2. This is different.
(D) PHOB : RJQD

P (+2) \(\rightarrow\) R
H (+2) \(\rightarrow\) J
O (+2) \(\rightarrow\) Q
B (+2) \(\rightarrow\) D
Pattern: All +2.
Step 3: Final Answer:
The pair BEYO : DGBQ is different because the shift for the third letter is +3 instead of +2.
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