Question:

In a bag there are some gold coins. In another bag there are 1/3rd extra gold coins as compared to the first bag. If the difference in the number of gold coins in the first and second bag is 5, then how many coins are there in the first bag?

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When “fraction extra” is mentioned, add it to the original quantity, then subtract to find the difference and solve for the original.
Updated On: Aug 14, 2025
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The Correct Option is D

Solution and Explanation

Step 1: Let the number of coins in the first bag be $x$
The second bag has $\frac{1}{3}$ extra coins than the first bag. So coins in second bag = $x + \frac{1}{3}x = \frac{4x}{3}$.
Step 2: Difference between the coins in second and first bag
Difference = $\frac{4x}{3} - x = \frac{4x - 3x}{3} = \frac{x}{3}$.
Step 3: Use given difference = 5
$\frac{x}{3} = 5$
$x = 15$
Step 4: Conclusion
The first bag contains 15 coins.
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