Step 1: Total number of coins.
Urvashi took out 40 coins. Let's assume the number of Rs.1 coins, Rs.2 coins, and Rs.5 coins that Urvashi took out are \( x \), \( y \), and \( z \) respectively. We know:
- \( x + y + z = 40 \)
- The total worth of the coins taken out is Rs.148, which gives the equation:
\[
1x + 2y + 5z = 148
\]
Step 2: Substituting and solving.
From these two equations, solve for \( x \), \( y \), and \( z \). The remaining coins in the bag will be \( 100 - x \), \( 100 - y \), and \( 100 - z \), respectively. The total worth of these remaining coins is Rs.212. Solve these equations to find the correct number of Rs.1 coins left.
Step 3: Conclusion.
The total number of Rs.1 coins left in the bag is \(\boxed{13}\).