Question

In a 2D seismic survey, first receiver location is at (1000 m, 4000 m), second receiver location is at (2000 m, 4000 m) and the source location is at (2000 m, 1000 m). Consider P-wave velocity as 5000 m/sec. The difference in first arrival time of P-wave phase for the two receivers is \(\underline{\hspace{1cm}}\) seconds.

Hint:

When calculating the difference in arrival times, use the difference in distances divided by the P-wave velocity.

Answer 1

Correct Answer: 0.03

The difference in arrival time can be calculated using the formula:
\[ \Delta t = \frac{ \text{Distance between source and receiver 1} - \text{Distance between source and receiver 2}}{\text{P-wave velocity}} \] \[ \Delta t = \frac{ \text{5000 meters}}{5000 \, \text{m/sec}} = 0.03 \, \text{seconds} \]