Initially, Pitcher A has 10 litres of wine, and Pitcher B has 10 litres of water. When 1 litre of water is transferred from B to A, the composition is:
- Pitcher A: 10L wine + 1L water = 11L mixture.
- Pitcher B: 9L water.
After mixing, 1 litre is removed from A and poured back into B. This 1 litre, consisting of 10/11 of wine and 1/11 of water (since the proportions are maintained), is transferred:
- Amount of wine in 1 litre = 10/11 L.
- Amount of water in 1 litre = 1/11 L.
By transferring this back to B, we calculate:
- Wine in B after transfer: 0 + 10/11 L = 10/11 L.
- Water in B after transfer: 9 + 1/11 L = 100/11 L.
Both pitchers return to 10 litres each. Thus:
- Water in A (initially 1L added) = 1 - 1/11 = 10/11 L.
- Wine in B = 10/11 L.
Hence, the water content in A is equal to the wine content in B, verifying the statement: The water contents in A is the same as the wine contents in B.