Question:
If y = x + tan x, then value of \(\frac{d^2y}{dx^2}\) at \(x= \frac{\pi}{4}\) is:
If y = x + tan x, then value of \(\frac{d^2y}{dx^2}\) at \(x= \frac{\pi}{4}\) is:
Updated On: May 18, 2024
- 1
- 2
- 4
- \(2 \sqrt{2}\)
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The Correct Option is C
Solution and Explanation
The correct option is (C): 4
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