Question

if \(y=\int\frac{e^{\tan x}dx}{\cos^2x(1+e^{2\tan x})}\) and y(0)=6 then y\(\frac{\pi}{4}\) is equal to

• A. tan^-1e-\(\frac{\pi}{4}\)
• B. tan^-1e+6-\(\frac{\pi}{4}\)
• C. tan^-1e-6+\(\frac{\pi}{4}\)
• D. tan^-1\(\frac{1}{e}\)-6+\(\frac{\pi}{4}\)

Answer 1

The Correct Option is B

The Correct answer is option is (B) : tan^-1e+6-\(\frac{\pi}{4}\)