Question:
if \(y=\int\frac{e^{\tan x}dx}{\cos^2x(1+e^{2\tan x})}\) and y(0)=6 then y\(\frac{\pi}{4}\) is equal to
if \(y=\int\frac{e^{\tan x}dx}{\cos^2x(1+e^{2\tan x})}\) and y(0)=6 then y\(\frac{\pi}{4}\) is equal to
Updated On: Apr 10, 2024
- tan-1e-\(\frac{\pi}{4}\)
- tan-1e+6-\(\frac{\pi}{4}\)
- tan-1e-6+\(\frac{\pi}{4}\)
- tan-1\(\frac{1}{e}\)-6+\(\frac{\pi}{4}\)
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The Correct Option is B
Solution and Explanation
The Correct answer is option is (B) : tan-1e+6-\(\frac{\pi}{4}\)
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