Step 1: Understanding the given general solution
We are given: \[ y = a e^{bx} + c e^{dx} + x e^{bx}. \] where \( a \) and \( c \) are arbitrary constants, and \( b \) is a fixed constant.
Step 2: Determining the order of the differential equation
The order of a differential equation is equal to the number of arbitrary constants in the general solution. In this case, the given solution contains two arbitrary constants: \( a \) and \( c \). Since we need to form a differential equation by eliminating these arbitrary constants, we differentiate successively.
Step 3: Differentiating the given function
Differentiating both sides with respect to \( x \): \[ y' = a b e^{bx} + c d e^{dx} + e^{bx} + b x e^{bx}. \] Differentiating again: \[ y'' = a b^2 e^{bx} + c d^2 e^{dx} + b e^{bx} + b e^{bx} + b^2 x e^{bx}. \] Since there are two arbitrary constants, differentiating twice is sufficient to eliminate them and obtain the required differential equation. Thus, the order of the differential equation is: \[ 2. \]
Step 4: Conclusion
Thus, the correct answer is: \[ 1. \]