Step 1: Understanding the given general solution
We are given: \[ y = a e^{bx} + c e^{dx} + x e^{bx}. \] where \( a \) and \( c \) are arbitrary constants, and \( b \) is a fixed constant.
Step 2: Determining the order of the differential equation
The order of a differential equation is equal to the number of arbitrary constants in the general solution. In this case, the given solution contains two arbitrary constants: \( a \) and \( c \). Since we need to form a differential equation by eliminating these arbitrary constants, we differentiate successively.
Step 3: Differentiating the given function
Differentiating both sides with respect to \( x \): \[ y' = a b e^{bx} + c d e^{dx} + e^{bx} + b x e^{bx}. \] Differentiating again: \[ y'' = a b^2 e^{bx} + c d^2 e^{dx} + b e^{bx} + b e^{bx} + b^2 x e^{bx}. \] Since there are two arbitrary constants, differentiating twice is sufficient to eliminate them and obtain the required differential equation. Thus, the order of the differential equation is: \[ 2. \]
Step 4: Conclusion
Thus, the correct answer is: \[ 1. \]
If the roots of $\sqrt{\frac{1 - y}{y}} + \sqrt{\frac{y}{1 - y}} = \frac{5}{2}$ are $\alpha$ and $\beta$ ($\beta > \alpha$) and the equation $(\alpha + \beta)x^4 - 25\alpha \beta x^2 + (\gamma + \beta - \alpha) = 0$ has real roots, then a possible value of $y$ is:
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))