We are given the system of equations:
\[
x + y = 7 \quad \text{and} \quad 3x - 2y = 11
\]
Solve the first equation for \(y\):
\[
y = 7 - x
\]
Substitute this into the second equation:
\[
3x - 2(7 - x) = 11 \quad \Rightarrow \quad 3x - 14 + 2x = 11 \quad \Rightarrow \quad 5x = 25 \quad \Rightarrow \quad x = 5
\]
Now substitute \(x = 5\) into \(x + y = 7\):
\[
5 + y = 7 \quad \Rightarrow \quad y = 2
\]
Thus, the correct answer is \(x = 5\), \(y = 2\).