Question:

If $x$ is real, then the minimum value of $x^2 - 8x+17 $ is

Updated On: Apr 14, 2024
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The Correct Option is A

Solution and Explanation

Let $y =x^{2}-8 x+17 $
$=(x-4)^{2}-16+17$
$=(x-4)^{2}+1 $
$\Rightarrow y \,\geq 1$ for all real values of x as
$(x-4)^{2} \geq \,0$
Hence , minimum value of y is 1
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Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.