Line joining $Q$ and $R$ can be parametrized as:
$Q = (2, 2, 1)$, $R = (5, 2, -2)$ ⇒ direction vector = $(3, 0, -3)$
Let $P = Q + \lambda(R - Q)$
$x_P = 2 + 3\lambda$, set $x_P = 4 \Rightarrow \lambda = \dfrac{2}{3}$
Then $y_P = 2 + 0 = 2$, $z_P = 1 - 3\cdot \dfrac{2}{3} = -1$
Check options — since y-coordinate = 2, and z = -2 matches option (2)