Question:
If the value of the double integral
\(\displaystyle\int^{4}_{x=3}\displaystyle\int^{2}_{y=1}\frac{dydx}{(x+y)^2}\)
is \(\log e (\frac{a}{24})\), then a is ____ (answer in integer).
If the value of the double integral
\(\displaystyle\int^{4}_{x=3}\displaystyle\int^{2}_{y=1}\frac{dydx}{(x+y)^2}\)
is \(\log e (\frac{a}{24})\), then a is ____ (answer in integer).
\(\displaystyle\int^{4}_{x=3}\displaystyle\int^{2}_{y=1}\frac{dydx}{(x+y)^2}\)
is \(\log e (\frac{a}{24})\), then a is ____ (answer in integer).
Updated On: Dec 12, 2024
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Correct Answer: 25
Solution and Explanation
The correct answer is:25 to 25
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