For a thin cylindrical shell under internal pressure, the longitudinal stress (\( \sigma_L \)) and the hoop stress (\( \sigma_H \)) are given by the formulas:
\[
\sigma_L = \frac{p D}{4t}, \quad \sigma_H = \frac{p D}{2t}
\]
Where \( p \) is the internal pressure, \( D \) is the diameter, and \( t \) is the wall thickness of the cylinder. The ratio of longitudinal pressure to hoop stress is:
\[
\frac{\sigma_L}{\sigma_H} = \frac{\frac{p D}{4t}}{\frac{p D}{2t}} = \frac{1}{2}
\]
Thus, the correct answer is \( \frac{1}{2} \).