If the sum of the interior angles of a polygon is \(1260^\circ\), how many sides does it have?
Show Hint
To find the number of sides of a polygon from the sum of interior angles, use the formula:
\((n - 2) \times 180^\circ = \text{sum of interior angles}\). Solve for \(n\).
Step 1: Use the formula for the sum of interior angles of a polygon.
The sum of the interior angles of an \(n\)-sided polygon is given by:
\[
\text{Sum of interior angles} = (n - 2) \times 180^\circ
\]
Step 2: Plug in the given sum.
We are given that the sum is \(1260^\circ\). So, we set up the equation:
\[
(n - 2) \times 180 = 1260
\]
Step 3: Solve for \(n\).
\[
n - 2 = \frac{1260}{180} = 7 \Rightarrow n = 7 + 2 = 9
\]
Hence, the polygon has \({9}\) sides.