To determine the value of β, we first need to find the slope of the line passing through the points (7, 17) and (15, β).
The slope of a line passing through two points (x₁, y₁) and (x₂, y₂) is given by:
\(m = \frac{{y_2 - y_1}}{{x_2 - x_1}}\)
For the given points (7, 17) and (15, β), the slope is:
\(m = \frac{{\beta - 17}}{{15 - 7}} = \frac{{\beta - 17}}{8}\)
Now, we know that a line is perpendicular to another line if and only if the product of their slopes is -1.
Therefore, we need to find the slope of the line \(2x - 3y + 17 = 0\) and determine the value of β that makes the product of the slopes -1.
The given line \(2x - 3y + 17 = 0\) can be rewritten in slope-intercept form as:
\(y = \frac{2}{3}x + \frac{17}{3}\)
Comparing this equation with the standard slope-intercept form \(y = mx + b\), we can see that the slope of this line is \(\frac{2}{3}\)
Now, we have:
slope of the line passing through (7, 17) and \((15, \beta) = \frac{{\beta - 17}}{8}\)
slope of the line \(2x - 3y + 17 = 0\)
To find β, we set the product of the slopes equal to -1:
\(\frac{{\beta - 17}}{8} \times \frac{2}{3} = -1\)
Simplifying the equation:
\((\beta - 17) \times \frac{2}{3}\)
Multiplying both sides by \(\beta = \frac{3}{2} + 17\)
\((\beta - 17) = -8 \times \frac{3}{2}\)(β - 17) = -8 * (3/2)
\(= -12\)
Solving for β:
\(β = -12 + 17 = 5\)
Therefore, β equals 5 (option C).
Given line: 2x - 3y + 17 = 0
We first find its slope.
Rewriting in slope-intercept form:
\[ 3y = 2x + 17 \Rightarrow y = \frac{2}{3}x + \frac{17}{3} \]
So, the slope of this line is \( \frac{2}{3} \).
Let the slope of the line joining points (7, 17) and (15, β) be: \[ m = \frac{\beta - 17}{15 - 7} = \frac{\beta - 17}{8} \]
Since the lines are perpendicular, the product of their slopes is -1: \[ \frac{2}{3} \cdot \frac{\beta - 17}{8} = -1 \]
Multiply both sides by 8: \[ \frac{2}{3} (\beta - 17) = -8 \Rightarrow 2(\beta - 17) = -24 \Rightarrow \beta - 17 = -12 \Rightarrow \beta = 5 \]
Correct answer: 5
First, let's find the slope of the line 2x - 3y + 17 = 0.
We can rewrite the equation in the slope-intercept form (y = mx + c):
3y = 2x + 17
y = (2/3)x + (17/3)
So, the slope of this line (m1) is 2/3.
The line passing through (7, 17) and (15, β) is perpendicular to the first line. The product of the slopes of two perpendicular lines is -1.
Therefore, m1 * m2 = -1, where m2 is the slope of the line passing through (7, 17) and (15, β).
(2/3) * m2 = -1
m2 = -3/2
Now, we can find the slope (m2) of the line passing through (7, 17) and (15, β) using the formula:
m2 = (y2 - y1) / (x2 - x1)
m2 = (β - 17) / (15 - 7)
m2 = (β - 17) / 8
We know that m2 = -3/2, so we can set up the equation:
(β - 17) / 8 = -3/2
β - 17 = -3/2 * 8
β - 17 = -12
β = -12 + 17
β = 5
Therefore, β equals 5.
Answer:
5
The foot of perpendicular from the origin $O$ to a plane $P$ which meets the co-ordinate axes at the points $A , B , C$ is $(2, a , 4), a \in N$ If the volume of the tetrahedron $OABC$ is 144 unit $^3$, then which of the following points is NOT on $P$ ?